To find N natural numbers not necessarily distinct such that their sum is equal to their product
2+2 =2×2
1+2+3=1×2×3
1+1+2=4=1×1×2×4
1+1+1+2+5=1×1×1×2×5
1+1+1+1+2+6=1×1×1×1×2×6
In general,
1+1+1+…..{(N-2) times}+2+N = 1×1×……{(N-2) times}×2×N
The above formula was published in Ramanujan Mathematical Society newsletter in June-2014 under problem and solution section.
1 comment:
Great post. Congratulations. ..
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